Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: my59vw on January 20, 2014, 04:53:49 PM
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I need help converting from percent chloride to percent zinc chloride. Is it as easy as
10% Cl x (136.315 ZnCl2 /35.453 Cl) = 38.45% ZnCl
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Chances are you are right. But without context it is hard to be sure.
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Well the problem is to calculate the zinc chloride and ammonium chloride concentration if the solution is 10% chloride. So I calculated the zinc chloride concentration as above as well as doing the same for ammonium chloride.
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Oops, there are no chances you are right, I am an idiot.
How many moles of ZnCl2 per mole of chlorine (hint: no formula for purpose)?
If the solution contains 10% of chlorides and is a mixture of zinc chloride and ammonium chloride, there is not enough data to solve.
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So it should be
10% Cl x (136.315 ZnCl2 /(2 x 35.453 Cl)) = 19.225% ZnCl2
For the ZnCl2 portion?
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Or So it should be
10% Cl x (136.315 ZnCl2 /(2 x 70.906 Cl2)) = 9.6125% ZnCl2
For the ZnCl2 portion?
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Yes, one of those.
2×70.906=141.8, so it would mean 136.3 g of ZnCl2 contains 141.8 g of Cl2.