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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: ajbarr on July 16, 2004, 01:04:19 AM

Title: reactions: substitutions, ketones and iodoform
Post by: ajbarr on July 16, 2004, 01:04:19 AM

I have three problems that I am struggling with:

CH3CH2CH2Br + CH3C(with three CH3's)attached to an 0-Na+
Is it really as simple as the Br and the Na "leaving" and the rest of the atoms attaching?

CH3C=OCH3 (a ketone) + H2
my friend thinks it is propane but I think it is propanol but am not sure where the second H goes.

thirdly, CH3C=OCH3 ( a ketone) + 3 NaOI gives me ? and then ? reacted with NaOH gives me ?
I think this might be an Iodoform reaction but am really lost here.

Thanks for any help. :)

Title: Re:reactions: substitutions, ketones and iodoform
Post by: AWK on July 16, 2004, 03:00:06 AM

CH3CH2CH2Br + CH3C(with three CH3's)attached to an 0-Na+
This is a simple method of ether synthesis

CH₃CH₂CH₂Br + (CH₃)₃ONa = CH₃CH₂CH₂-O-C(CH₃)₃
Depending on reaction conditions a small amount of an elimination product CH₂CH=CH₂ can be expected.

CH3C=OCH3 (a ketone) + H2
(CH₃)₂C=O + H2 = CH₃-CHO_H-CH₃ 2-propanol (or isopropyl alcohol)


CH3C=OCH3 ( a ketone) + 3 NaOI
CH₃-CO-CH₃ + 3 NaOI --> CH₃-CO-CI₃
CH₃-CO-CI₃ + NaOH = CH₃COONa + CHI₃