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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Asurath on April 11, 2014, 11:49:05 AM

Title: Help: normality and molarity of iodine and sodium thiosulfate
Post by: Asurath on April 11, 2014, 11:49:05 AM

Hey,

Could anyone explain to me the following:
Why is 1N Na2S2O3*5H2O equal to 1M Na2S2O3*5H2O? Could you explain the process of conversion.
Why is 1N Iodine equal to 0.5M Iodine? Could you explain the process of conversion.

What to know:
Molar mass of Na2S2O3*5H2O = 248.18g/mol
Molar mass of I2 = 253.80g/mol
N - normality
M - molarity (molar concentration)

Title: Re: Help: normality and molarity of iodine and sodium thiosulfate
Post by: Borek on April 11, 2014, 12:58:42 PM

Try to write reaction equations (half reaction equations to be precise).

See how many electrons are exchanged per S₂O₃^2- and per I₂.