Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: JMaria on July 28, 2014, 10:05:14 PM
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So I have a reaction with 2-methyl-2-octene (lq) and HCl (lq) with heat and CH2Cl2.
I think the HCl adds in Markovnikov fashion but I've only seen the CH2Cl2 associated with halogenation and the heat with radical reactions so I'm not sure what it's there for.
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As a solvent?
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Well it has the 2-methyl-2-octene and then + HCl and then an arrow beside it with a delta on top and a CH2Cl2 on the bottom.
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Then it is a solvent
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So is the product 2-chloro-2-methyloctane? And the heat is required for the reaction to occur and the methylene chloride is the solvent which can be in excess?
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Yes, that is the product. Heat speeds the reaction up exponentially (kforward), and it increases the yield (kforward/kbackwards. The solvent is in excess.