Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: unsu on August 14, 2014, 01:09:47 PM
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Does anyone know how to derive a term symbol for a Cr atom?
Because its configuration is 4s(1)3d(5)
To get a term symbol we must consider a sub-shell with a specific value of l.
In Cr atom there are two unoccupied orbitals with l=0 and l=1
So, any idea how to derive a term symbol for Cr?
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The same way you do any other electron configuration. Are you familiar with how to determine term symbols - generally?
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oookk... then:
4s(1)3d5
ML = 0 + 2 + 1 + 0 + (-1) + (-2) = 0
L = S
max Ms = 6*(1/2) = 3
S = 3
Ground state configuration term symbol = 7S
Am I correct? :)
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This is what I got as well. Now can you determine the rest of them? :)
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if we allow the electrons to pair up, even on 4s orbital,
then there are 12 positions for 6 electrons, there must be 924 micro states >:D
if we can do whatever we want with d electrons but leave one electron on 4s orbital, then there are 2x256=504 micro states (2 because 4s :spinup: and 4s :spindown:)
no pairing = 26 = 64 microstates
plus different J values :o :o :o
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if we can do whatever we want with d electrons but leave one electron on 4s orbital, then there are 2x256=504 micro states (2 because 4s :spinup: and 4s :spindown:)
Well if you don't adhere to this restriction, then you're in another electron configuration, so...
I went through it quickly and (excluding J states) I found the following: 7S, 3I, 1I, 3H, 1H, 5G, 5F, 5D, 5P, 3x3G, 3x3F, 3x3D, 2x3P, 2x1G, 4x1D, 1P.
I wonder if I'm right. Maybe we'll never know. :)