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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: bellerocks94 on October 11, 2014, 05:37:45 PM

Title: Solutions Lab
Post by: bellerocks94 on October 11, 2014, 05:37:45 PM

Please help me find these values and explain how you got them, thank you!!

2. Calculate the mass (in g) of sucrose needed to make 50 mL of a 30% (m/v) solution.
(.30)x(50mL)=15g....Not sure if this is right
3. Calculate the mass (in g) of sucrose needed to make 50 mL of a 1.75 M sucrose solution.
17.5M/0.05=350g...Have no idea on this one
4. Convert the concentration of the 1.75 M sucrose solution from question 3 into units of mass/volume percent, % (m/v).
350g/50ML= 700% M/V

Title: Re: Solutions Lab
Post by: Borek on October 11, 2014, 05:50:34 PM

You have to show your attempts at solving the question to receive help. This is a forum policy.

Title: Re: Solutions Lab
Post by: bellerocks94 on October 11, 2014, 07:12:58 PM

Okay I did now.

Title: Re: Solutions Lab
Post by: Borek on October 12, 2014, 02:57:24 AM

Quote from: bellerocks94 on October 11, 2014, 05:37:45 PM

2. Calculate the mass (in g) of sucrose needed to make 50 mL of a 30% (m/v) solution.
(.30)x(50mL)=15g...

OK

Quote

3. Calculate the mass (in g) of sucrose needed to make 50 mL of a 1.75 M sucrose solution.
17.5M/0.05=350g...

Looks like you have no idea what M is.

http://www.chembuddy.com/?left=concentration&right=molarity

How many moles of sucrose in the solution?