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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: 4kec4 on October 14, 2014, 09:25:51 PM

Title: Cyclohexyl Bromide from Cyclohexanol
Post by: 4kec4 on October 14, 2014, 09:25:51 PM
I would appreciate if you could help me out understand these questions regarding my organic chem lab:

1) Why was your product dried over the more powerful CaCl2 rather than the more selective Na2SO4? (Note: Ca2+ attracts electrons better than Na1+)

2) Clearly explain the value of using the CH2Cl2. Why is diethyl ether no used in this seperation? (Hint: density of bromocyclohexane is 1.32)

3) In which step was most of your product lost? How might this have been minimized?
Title: Re: Cyclohexyl Bromide from Cyclohexanol
Post by: Babcock_Hall on October 15, 2014, 08:51:09 AM
It is a forum rule that you must show your attempt first before we can help you.  But I will give you some very general thoughts about drying solvents.  The various inorganic salts have different properties, including their capacity for water and their efficiency to remove water.
Title: Re: Cyclohexyl Bromide from Cyclohexanol
Post by: 4kec4 on October 15, 2014, 11:51:34 PM
I appreciate the reminder, I am a brand new member. Also, thanks for the hint.
Title: Re: Cyclohexyl Bromide from Cyclohexanol
Post by: Dan on October 16, 2014, 03:16:31 AM
Quote from: 4kec4 on October 14, 2014, 09:25:51 PM
I would appreciate if you could help me out understand these questions regarding my organic chem lab:

1) Why was your product dried over the more powerful CaCl2 rather than the more selective Na2SO4? (Note: Ca2+ attracts electrons better than Na1+)

2) Clearly explain the value of using the CH2Cl2. Why is diethyl ether no used in this seperation? (Hint: density of bromocyclohexane is 1.32)

3) In which step was most of your product lost? How might this have been minimized?

You will also need to post the procedure for us to help you.