Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: unsu on December 01, 2014, 03:43:39 AM
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Is is possible? And what are the possible products?
I suggest Br2+AgNO3 :rarrow: AgBr :spindown:+BrNO3
What do you think?
Update: I still think it is highly unlikely to get BrNO3. Probably in aqueous solution the silver ions just shift the equilibrium of the bromine hydrolysis to form Br- and BrO3-:
Br2+AgNO3+H2O :rarrow: AgBr :spindown: + HBrO3 + HNO3
or
Br2+AgNO3+H2O :rarrow: AgBr :spindown: + HBrO + HNO3
Thoughts?
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Bromine in water stay in an equilibrium what is almost on left side.
Br2 + H2O => HBr + HOBr
If you add silver ion you will shift it more to the right side.
AgBr will precipitate.
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Bromine in water stay in an equilibrium what is almost on left side.
Br2 + H2O => HBr + HOBr
If you add silver ion you will shift it more to the right side.
AgBr will precipitate.
Thanks! I read that HOBr is very unstable in water at temperatures above 0 °C, it will disproportionate to bromate and bromide, so the products at normal conditions would likely be:
Br2+AgNO3+H2O :rarrow: AgBr :spindown: + HBrO3 + HNO3
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Equation is not balanced.