Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Pipo87 on January 12, 2015, 01:39:58 PM
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Hello
I'm trying to balance the following reaction (in acid):
CH3CH2OH + MnO42- --> CO2 + Mn2+
I can balance the half reaction for manganate (oxidant), that one is easy:
8H+ + MnO42- + 4e- <> Mn2+ + 4H2O
But the halfreaction for ethanol (reductant) just doesn't seem right, I can't balance it:
H2O + CH3CH2OH <> 2CO2 + 8H+ + 7e- + 5e-
The mass is balanced this way, but the electric charges aren't, I can't figure out how :(
Probably should note that I'm a first grade chemistry student, the reaction I'm trying to balance is for school work
Thanks for any help at all!
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Never mind I missed something completely, and that is that the O's weren't balanced yet
so it's like this:
3H2O + CH3CH2OH <> 2CO2 + 12H+ + 7e- + 5e-
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The half-reaction for the permanganate that you wrote is not correct.
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It was manganate, not permanganate. Though the oxidation state diagram that I posted here http://www.chemicalforums.com/index.php?topic=78280.0
would suggest that in acid it is unstable to disproportionation to MnO4- and MnO2.
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One thing you need to correct is the charge on the permanganate ion.
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One thing you need to correct is the charge on the permanganate ion.
As mjc already wrote - question asks for manganate, not permanganate, and the formula of magnanate is OK.
in acid it is unstable to disproportionation to MnO4- and MnO2.
I don't think it matters much for the final answer. While it would mean there are two possible paths for the oxidation, final (overall) reaction equation would be the same.
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It was manganate, not permanganate.
Sorry, it did not notice that. Normally people use permanganate to oxidize organic substrates, I never saw anyone using manganate to oxidize the substrates. But anyway, I would like Pipo87 to comment on this to make sure this wasn't a mistake :)
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It wasn't a mistake, it really is manganate :p
I also noticed permanganate it much more common, when I tried googling for this reaction before. Actually I did not find any results at all for this reaction with manganate
Though it's not a reaction we used in practice, just a theoretical exercise i had to complete.
Thanks for the feedback anyways, but as I posted before, I managed to find my own silly mistake already
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It was manganate, not permanganate. Though the oxidation state diagram that I posted here http://www.chemicalforums.com/index.php?topic=78280.0
would suggest that in acid it is unstable to disproportionation to MnO4- and MnO2.
mjc,
How realistic is the question as written?