Chemical Forums

Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: anna.kolinski on January 26, 2015, 06:07:47 PM

Title: What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....
Post by: anna.kolinski on January 26, 2015, 06:07:47 PM

Does anybody know what the nuclear spin, I, of Mo(V) and Fe(IV) is?

I'm trying to work out the number of lines that 2nI+1 gives, but the main isotopes have an I = 0 I think (but I'm not sure).

Also, if the main isotopes give I=0, can it still be worked out for the less common isotopes?

Thanks

Title: Re: What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....
Post by: Babcock_Hall on January 26, 2015, 06:22:27 PM

http://www-usr.rider.edu/~grushow/nmr/NMR_tutor/periodic_table/nmr_pt_frameset.html

Title: Re: What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....
Post by: Enthalpy on January 28, 2015, 10:09:06 AM

Also there, section "isotopes":

http://www.webelements.com/iron/
only ⁵⁷Fe with 2.1% natural abundence has spin 1/2

http://www.webelements.com/molybdenum/
only ⁹⁵Mo (15.9%) and ⁹⁷Mo (9.6%) have spin 5/2.