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Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: strugglingstudent on February 24, 2015, 03:49:22 PM

Title: [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?
Post by: strugglingstudent on February 24, 2015, 03:49:22 PM

If I am making a complex ion with ammonia solution and copper (II) hydroxide precipitate, would the complex ion be [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?

[Cu(NH₃)₄]²⁺ would have a square planar shape and have bond angles of 90ᵒ
but
[Cu(NH₃)₄(H₂O)₂]²⁺ would have an octahedral shape and have bond angles of 109ᵒ

which one am I making? Any help would be very useful. Thank you :)

Title: Re: [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?
Post by: sjb on February 24, 2015, 05:00:31 PM

Quote from: strugglingstudent on February 24, 2015, 03:49:22 PM

If I am making a complex ion with ammonia solution and copper (II) hydroxide precipitate, would the complex ion be [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?

[Cu(NH₃)₄]²⁺ would have a square planar shape and have bond angles of 90ᵒ
but
[Cu(NH₃)₄(H₂O)₂]²⁺ would have an octahedral shape and have bond angles of 109ᵒ

which one am I making? Any help would be very useful. Thank you :)

How do you propose octahedral shape and bond angles of 109ᵒ

Title: Re: [Cu(NH₃)₄]²⁺ or [Cu(NH₃)₄(H₂O)₂]²⁺ ?
Post by: mjc123 on February 25, 2015, 05:53:13 AM

The complex ion has a charge of 2+, not 2-.