Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: moni on April 10, 2006, 12:27:21 PM
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a) the ionization constant Ka of formic acid ,HCO2H is 1.80 *10^-4. What is the percent ionization of a 0.00100 M solution of this acid?
b)The pH of a 0.072 M solution of benzoic acid HC7H5O2 is 2.86.compute Ka for this acid?
c)What concentration of acetic acid HCH3CO2 is needed to give a [H+]=3.5 *10^-4? Ka = 1.75 *10^-5
For the a) i'm not sure but :
HCO2H ----> HCO2- + H+
% ionization =HCO2H/H+ *100%
Ka = [HCO2-][H+]/[HCO2H]
1.8*10^-4 = (x)(x)/0.417M
x^2=(1.8*10^-4)(0.417)
x=8.6*10^-3
% ionization= 1.80*10 ^-4/8.6*10^-3 *100%
% ionization = 2.09%
am i on the right truck?
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1.8*10^-4 = (x)(x)/0.417M
What is 0.417?
Regardles of where did you get this number from - the equation is wrong. Numerator depends on x.
am i on the right truck?
Depends on where you are going :)
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Numerator depends on x.
what does it mean?
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Sorry - I meant denominator is a function of x (numerator is function of x too, but that is already visible in your formula).
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but like u said the equation is wrong,that means everything is wrong
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You are - unfortunately - right.
http://www.chembuddy.com/?left=pH-calculation&right=pH-weak-acid-base
http://www.chembuddy.com/?left=BATE&right=pH-cheat-sheet
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HCO2H + H2O----> HCO2- + H3O is it right?
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Yes, but you may safely omit water for these calculations, and assume it is H+, not H3O+. There is less writing when solving ;)
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HCO2H ----> HCO2- + H+ so that is good too
Ka is wrong, but from Ka = [H][A] /[HA]
Ka = [HCO2-][H+] / [HCO2H]
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So far so good.
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1.8 *10^-4 =(x)(x) /x-0.0100
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0.01 or 0.001?
And x-0.01 or 0.01-x?
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0.01-x
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So far so good. What next?