Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Chemistry Olympiad and other competitions => Topic started by: T on July 18, 2015, 06:37:56 PM
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Hello,
The question is:
Butane has a vapour pressure of 47.156 kPa at 253 K, and 149.03 kPa at 283 K. Is butane gaseous or non-gaseous under the following conditions:
Temp. = 253 K Pressure = 1 atm
Temp. = 253 K Pressure = 2 atm
Temp. = 283 K Pressure = 1 atm
Temp. = 283 K Pressure = 2 atm
So firstly, I have searched what vapour pressure means. And from what I read, vapour pressure is the pressure of the vapour of a liquid at equilibrium in a closed system. And can only affected by temperature.
So since butane has a vapour pressure of 47.156 kPa at 253 K, at 253 K and 1 atm the vapour pressure of butane would still be 47.156 kPa. However, I am not sure how the external pressure would affect the physical state of butane. Could someone explain this? Also does the 1 atm mean that in a closed system, the pressure in it is 1 atm?
Thanks
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What happens when the vapour pressure of a liquid is greater than the external pressure?
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The liquid boils doesn't it?
So when butane has:
Temp. = 283 K Pressure = 1 atm
It would be gaseous?
And for the others it would be non-gaseous?
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Correct
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Thanks mjc123