Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: confusedstud on August 23, 2015, 03:59:41 AM
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Is there a way to show that it is the maximum non expansion work? I was thinking delta U=q+w and the w is replaced with the ΔG?
I'm not very sure how do we relate it back to internal energy.
Thanks
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G=H-TS
So you can write
dG = dU + pdV + Vdp - TdS - sdT
If T and P are constant:
dG= dU + pdV - Tds
Now dU is q+w+w' where w is the expansion work (-pdV) and w' is the non-expansion work.
dG = q-pdV+w'+pdV -Tds
dG= q+w'-Tds
but q=Tds (rev) or q>_Tds
so
dG = w'