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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: elfishies on January 30, 2016, 07:39:22 PM

Title: Balancing redox equation
Post by: elfishies on January 30, 2016, 07:39:22 PM

How do you balance this equation?

IO3{-} + I{-} + H{+} = I3{-} + H2O

I tried using oxidation numbers but there seems to only be reduction?

Title: Re: Balancing redox equation
Post by: mikasaur on January 30, 2016, 08:20:11 PM

What do you consider to be the reduction?

Do you think there might be an oxidation going on as well?

Title: Re: Balancing redox equation
Post by: elfishies on January 30, 2016, 08:56:29 PM

reduction: IO3- --> I3-
the oxidation number for I goes from +5 to -1

sorry, I can't seem to see any oxidation reaction

***edit: I think I figured it out, thanks!***

Title: Re: Balancing redox equation
Post by: mikasaur on January 30, 2016, 09:28:36 PM

Did you? Nice!

Mind showing us what you did (at least the first couple steps)?

Title: Re: Balancing redox equation
Post by: AWK on January 31, 2016, 02:22:32 AM

Oxidation number of iodine in I₃^- is not equal to -1

Title: Re: Balancing redox equation
Post by: Hunter2 on January 31, 2016, 01:32:27 PM

One more hint:
Check what is I₃^-. Divide this molecule fpr easier calculation.