Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Organic Spectroscopy => Topic started by: jamesrb on May 03, 2016, 09:08:11 PM
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Am I correct in assume that in 13CNMR spectroscopy proton decoupled spectrums still show 13C-19F coupling? And that a proton coupled spectrum would show both 13C-19F and 13C-1H coupling? So in CH2F2 for the proton decoupled spectrum we would see 3 lines (1 triplet). And in the proton coupled spectrum we would see 6 lines, 2 triplets (as the coupling constant for C-H and C-F are different).
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That looks mostly correct, except for your last sentence. Make a coupling tree and see what happens.
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1 pentet?
H1=α
H2=α
F1=α
F2=α
H1=α
H2=β
F1=α
F2=α
etc. etc. etc.
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Would you expect 2JCH and 2JCF couplings to be the same?
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@OP, I am not following what you wrote.
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Would you expect 2JCH and 2JCF couplings to be the same?
I would not expect 2JCH and 2JCF to be the same.
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@OP, I am not following what you wrote.
Instead of scanning my drawing of the coupling tree I just summarized what I thinking regarding the spins of the four atoms attached to the carbon. There are two hydrogen atoms: H1 and H2 and two fluorine atoms: F1 and F2. When I drew the tree I came up with five lines. Now I am thinking there should be 8. I have never drawn a coupling tree before and this may not be the best molecule to start with but none the less I tried:
(https://www.chemicalforums.com/proxy.php?request=http%3A%2F%2Fs32.postimg.org%2Fu95my7tup%2FCH2_F2.jpg&hash=541fc288296a84d6a8c4bb39f81bfe354277b209) (http://postimg.org/image/u95my7tup/)
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The H-1 decoupled spectrum is a 1:2:1 triplet, due to coupling from fluorine. If one mentally turns off the H-1 decoupler, each triplet should split into a triplet. I believe that there will be 9 lines.
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It should be a triplet of a triplet (=9 lines). the number of lines will depend on the magnitude of the couplings and the resolution.