Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: chelle on August 25, 2016, 04:29:53 AM
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Hi,
I have a solution of 150 mM of ammonium acetate in water. How do I calculate the osmolarity of this solution?
I understand that an osmole (Osmol) is 1 mol of particles that contribute to the osmotic pressure of a solution and that NaCl breaks into two particles in solution (both Na and Cl), thus giving 2 Osmols/liter. I just don't know how to do this for ammonium acetate!
From my reading online it seems ammonium acetate will disassociate into CH3COO- (aq) + NH4+ (aq), giving 2 particles in solution and thus be 2 Osmols. If this is the case the osmolarity would be 300. Is this correct?
Any help would be most welcome!
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Caution : In case of NaCl , there is one assumption associated that NaCl dissociates 100% into Na+ and Cl- .
Do you think Ammonium Acetate will completely dissociated ?? (Figure out Why NaCl dissociated 100% )
Do you know about dissociation constant ?? What is the dissociation constant of Ammonium Acetate ??
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Is this correct?
It is a very good approximation.
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Is this correct?
It is a very good approximation.
Sorry I read something wrong .
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Whether the ammonium acetate completely ionises or not, there will be two moles of species in solution, because there are two on either side of the equation:
NH4OAc(s) :rarrow: NH4+(aq) + AcO-(aq) ::equil:: NH3(aq) + HOAc(aq)
There are no NH4OAc "molecules" in solution. Of course there will be a tendency for NH3 to come out into the gas phase (you can smell it) but to a first approximation you will get 2 moles of dissolved species per mole of NH4OAc. The osmolarity will of course be 0.300, not 300.
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Of course there will be a tendency for NH3 to come out into the gas phase (you can smell it)
Smell of acetic acid is much more intense!