Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Organic Spectroscopy => Topic started by: gk000 on October 03, 2016, 12:22:57 AM
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Hi
Undergrad organic chem
Ive been struggling with working out the fragmentation pattern of my unknown molecule. I definitely know its cyclopropyl phenylmethanol. Just cant figure out some of the fragmentation
Peak Intensity Assignment
149 5 C10H12O
131 100 [C10H10]+
120 20 ----
107 7 ------
91 10 [C7H6]+
71 61
I've calculated the losses from each peak. Between peaks 131 to 120, the loss is 11 which I'm really confused about what would break off. I know m/z 91 is a tropylium ion which would generally break down to a benzyl ion. Not sure if I'm just going about it the wrong way.
Structure image attached
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You have started this problem the right way, by tabulating the ions & intensities....BUT note,
1. Highest mass ion is M+. which is at m/z 148 for Molecular formula C10H12O1
2. m/z 149 is due to the 13C and 2H isotopic contributions----ignore it !!
3. your tabulation is now
m/z
148 C10H12O1
131
120 etc...
91 is C7H7+ not C7H6
Obviously, m/z 120 is not derived from 131, and 107 is not derived from 120 etc. In these situations, go to the next higher m/z value----is m/z 120 from m/z 148 ?? Is m/z 107 from 131 or 148 ?
You are almost there, stay with it and it will fall out !!!!!
NB I have assumed electron ionization (which would give M+. at m/z 148; positive chemical ionization WOULD give [M+H]+ at m/z 149) check with prof. or the TA to find out what ionization method was used.
Regards
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2. m/z 149 is due to the 13C and 2H isotopic contributions----ignore it !!
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why m/z 148 and 130 are absent?
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why m/z 148 and 130 are absent?
They are absent because it has to be a positive CI mass spectrum. I had initially assumed an EI spectrum, because that is what is almost always presented to undergrad organic students.
That led me to put in the NB, because I started to get second thoughts about the spectrum that he was working with.
Regards
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Spectrum presented by gk000 is pure (without isotopic contributions). Alcohols very often give m/z M+1 (MH+). This ion eliminates water.
130 = M+-28(C2H4)
My printing error - should be 120
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AWK,
I have not run an EI spectrum in more than 25 years, so will take your word for it.
However, we don't want to confuse gk000 with statements like
m/z 130 is M+ - C2H4
Regards
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Elimination of ethylene is typical for cyclopropane derivatives.
See, eg ethylcyclopropane
http://webbook.nist.gov/cgi/cbook.cgi?ID=C1191964&Mask=200
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Yes, but MW is not 158 is it ?
Regards
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Yes, but MW is not 158 is it ?
Regards
Sorry for my previous fault, but 158 is a back interpretation of this printing error.