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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: xxdakee on January 11, 2017, 04:43:41 PM

Title: Hydrolysis
Post by: xxdakee on January 11, 2017, 04:43:41 PM

Al2S3 + 6H2O = 2Al(OH)3 + 3H2S
Can someone explain this reaction to me? Why this is a hydrolysis? And why Al2O3 can't be a product of this reaction instead of Al(OH)3?


I'm 100% sure that this reaction is correct, but I can't find any argument to prove it.

Title: Re: Hydrolysis
Post by: AWK on January 11, 2017, 06:18:14 PM

Do you know a definition of hydrolysis?

Title: Re: Hydrolysis
Post by: xxdakee on January 12, 2017, 06:15:32 AM

Yes I know :)

Title: Re: Hydrolysis
Post by: AWK on January 12, 2017, 06:34:43 AM

Then this reaction should be obvious.

Title: Re: Hydrolysis
Post by: xxdakee on January 12, 2017, 06:56:03 AM

But for my teacher its not lol. She said that the products of this reaction are Al2O3 and H2S

Title: Re: Hydrolysis
Post by: AWK on January 12, 2017, 07:20:28 AM

When you treat Al₂S₃ with water vapors at temperature over 400 C then anhydrous Al₂O₃ is formed. Formation of boehmite (AlOOH) starts about 200 C.
Since Al(OH)₃ always contains some water its formula is sometimes written as Al₂O₃·nH₂O. But without H₂O below 400 C it is a nonsense.

Title: Re: Hydrolysis
Post by: xxdakee on January 12, 2017, 08:41:30 AM

Thanks :) That's all I need :)