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Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: GeLe5000 on February 12, 2017, 04:05:13 PM

Title: Balance of a combustion equation.
Post by: GeLe5000 on February 12, 2017, 04:05:13 PM
Good evening.

It's easy to balance a combustion equation for molecules made of C, H and O. But how can I know the fate of a molecule containing a N atom ?
For example : Paracetamol, C8H9NO2 + ? O2  ------> ? H2O + ? CO2 + ? N2.
Title: Re: Balance of a combustion equation.
Post by: Borek on February 12, 2017, 04:54:29 PM
N2 is in most cases a reasonable guess.
Title: Re: Balance of a combustion equation.
Post by: Enthalpy on February 12, 2017, 06:47:23 PM
If the combustion gave CO2 instead of a mix with much CO, then the oxidizer was not pure oxygen, but something like air, which already brings much nitrogen. So what should be different if the fuel too contains nitrogen?
Title: Re: Balance of a combustion equation.
Post by: GeLe5000 on February 13, 2017, 02:02:08 AM
I was considering combustion in a calorimeter, in pure oxygen. And the production of N2 is (indeed) only a guess.

Title: Re: Balance of a combustion equation.
Post by: Enthalpy on February 13, 2017, 09:39:27 AM
While the combustion gases are hot, they contain much CO, some NOx and many more species. But once they have cooled enough to leave only CO2 without CO, N2 is the expected product.

Out of curiosity, I've asked a software the composition of the flame, at 1atm, with just enough pure oxygen for CO2 once cold. Here molar fractions:

CO                   2.8109e-001
CO2                  1.8832e-001
COOH                 7.2469e-007
H                    4.1505e-002
HCO                  7.9666e-007
HNO                  6.5391e-007
HNO2                 7.9769e-008
HO2                  4.4565e-005
H2                   3.3417e-002
HCOOH                1.8394e-008
H2O                  1.7123e-001
H2O2                 1.2297e-006
N                    4.7924e-006
NH                   3.5205e-007
NH2                  3.4576e-008
NO                   7.4103e-003
NO2                  2.9766e-006
N2                   2.5629e-002
N2O                  7.6986e-008
O                    5.7822e-002
OH                   7.7243e-002
O2                   1.1627e-001
O3                   7.1936e-008
Title: Re: Balance of a combustion equation.
Post by: GeLe5000 on February 13, 2017, 03:49:53 PM
Thank you for the data.

It's far from the simplicity of : Glucose C6H12O6 + 6 O2 ---------> 6 CO2 + 6 H2O.

Title: Re: Balance of a combustion equation.
Post by: AWK on February 13, 2017, 11:48:19 PM
Quote
For example : Paracetamol, C8H9NO2 + ? O2  ------> ? H2O + ? CO2 + ? N2

Nobody use paracetamol as fuel in  the car engine. Even then catalyst convert CO and NO and other dangerous compounds that may be formed during combustion to N2 and CO2.

Just end balancing this above reaction and all be OK
Title: Re: Balance of a combustion equation.
Post by: GeLe5000 on February 14, 2017, 02:32:52 AM
C8H9NO2 + 37/2 O2  -----> 8 CO2 + 9/2 H2O + 1/2 N2
Title: Re: Balance of a combustion equation.
Post by: AWK on February 14, 2017, 02:36:53 AM
Whole numbers and ... correct balancing.
Title: Re: Balance of a combustion equation.
Post by: Borek on February 14, 2017, 04:08:44 AM
Out of curiosity, I've asked a software the composition of the flame, at 1atm, with just enough pure oxygen for CO2 once cold. Here molar fractions:

The OP asked about burning in an excess of pure oxygen, so while these numbers are interesting they are irrelevant to the case.
Title: Re: Balance of a combustion equation.
Post by: GeLe5000 on February 14, 2017, 04:45:48 AM
It must be this one :

4 C8H9NO2 + 37 O2  -----> 32 CO2 + 18 H2O + 2 N2

I was asking about that because of the metabolic fate of Paracetamol. For 1 molecule of Paracetamol, there is 37/4 = 9,25 molecules of Oxygen consumed, thus there must be an Oxygen radical somewhere. A toxic species.

The same with Ibuprofen (C13H18O2 + 16,5 O2 ---> 13 CO2 + 9 H2O). I hope there's no mistake in this one.

But I don't know if it could be an explanation of the toxicity of these drugs.
Title: Re: Balance of a combustion equation.
Post by: AWK on February 14, 2017, 05:01:27 AM
Quote
C13H18O2 + 16,5 O2 ---> 13 CO2 + 9 H2O
Quote
Coefficients should be whole numbers.
Title: Re: Balance of a combustion equation.
Post by: Arkcon on February 14, 2017, 05:51:44 AM
It must be this one :

4 C8H9NO2 + 37 O2  -----> 32 CO2 + 18 H2O + 2 N2

I was asking about that because of the metabolic fate of Paracetamol. For 1 molecule of Paracetamol, there is 37/4 = 9,25 molecules of Oxygen consumed, thus there must be an Oxygen radical somewhere. A toxic species.

The same with Ibuprofen (C13H18O2 + 16,5 O2 ---> 13 CO2 + 9 H2O). I hope there's no mistake in this one.

But I don't know if it could be an explanation of the toxicity of these drugs.

Its not rare, in biology, to balance a metabolic equation with fractions.  But before you said:

I was considering combustion in a calorimeter, in pure oxygen. And the production of N2 is (indeed) only a guess.

You're going to have to pick one or the other.  Nothing like a calorimeter happens in any living thing.
Title: Re: Balance of a combustion equation.
Post by: GeLe5000 on February 14, 2017, 06:09:07 AM
"Nothing like a calorimeter happens in any living thing"


I agree, but the total energy balance for the reaction "Glucose C6H12O6 + 6 O2 ---------> 6 CO2 + 6 H2O + Energy (ATP)"  is given buy a measurement in a calorimeter, thus I thought that it would be the same for any compound (assuming that it can be catabolised on the same way as Glucose. Aspirin, for example can be a source of energy in our body : C9H8O4 + 9 O2   ----> 9 CO2 + 4 H2O + Energy (ATP)).
Since the enzymes handle their substrates one by one, a biochemist must sometimes use fractions. And an odd number of Oxygen atoms could mean that an Oxygen radical leaks away.



Title: Re: Balance of a combustion equation.
Post by: AWK on February 14, 2017, 06:45:58 AM
Quote
Aspirin, for example can be a source of energy in our body : C9H8O4 + 9 O2   ----> 9 CO2 + 4 H2O + Energy (ATP)).
Aspirin is not a source of energy for our body, at least not important one.
About 70 % of aspirine is excreted in urine as salicylic acid, its acyl and phenolic glucuronides, salicyluric acid, its phenolic glucuronide and gentisic acid. Conjugation needs some energy.

https://www.ncbi.nlm.nih.gov/pubmed/3705620
Title: Re: Balance of a combustion equation.
Post by: GeLe5000 on February 14, 2017, 08:29:30 AM
Thank you for the link.

Of course Aspirin is not an important source of energy in our body. But this metabolic pathway was mentioned in a pharmacology book and this annoyed me for the following reason.
I'm testing different compounds on the growth of protozoan cultures.
No surprise : Glucose increases their divison rate. The same with Vitamin C.
But more interesting : Aspirin also increases the division rate. So, I must ask myself it's because of a production of energy from this molecule. For now, I haven't managed to find a way of answering this question.
Also interesting : Ibuprofen is toxic down to 0.0001 M. That's another problem. And according to the literature, Paracetamol, which I haven't tested yet, could do the same.
That's why I'm glad to have found here the basic chemistry : correct combustion equations.
Title: Re: Balance of a combustion equation.
Post by: AWK on February 14, 2017, 08:38:28 AM
Of course, bacteria, fungi or protozoa may use quite odd compounds as source of carbon and nitrogen (if they are not toxic for them).