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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: galle89 on February 19, 2017, 09:26:13 AM

Title: dilute of HNO3
Post by: galle89 on February 19, 2017, 09:26:13 AM

Hello guys

Please excused my english skills. I am from germany.

Currently I try to dilute or better create a 0,1 mol/l HNO3 acid. My parent substance is a 53% HNO3 whitout other data.

I need to run a electrolysis a 0,1 mol/l HNO3. Maybe my chemestry skills are very low, althougt I have a degree in a chemeststy similar profession. But I today I work in a other job, so that my chemestry skills fall day by day.

HNO3 = M = 63g/mol
W = 53%

But I have no idea how it goes on? Can anybody tell me, how I can fix this problem?

Greating

Title: Re: dilute of HNO3
Post by: AWK on February 19, 2017, 10:00:47 AM

You need density of concentrated HNO₃ for calculation of its molar concentration.

Title: Re: dilute of HNO3
Post by: galle89 on February 20, 2017, 09:50:33 AM

Hello AWK

That means 65% HNO3? Is that correct?

Thanks

Title: Re: dilute of HNO3
Post by: AWK on February 20, 2017, 09:59:18 AM

At the first post you informed us about 53 % HNO₃.
Commercial concentrated nitric acid is 67.0-69.0% with density 1.40 to 1.42.
Having know density and concentration you can calculate molarity of this acid and then you can easily dilute it.