Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: foxfourfive on March 22, 2017, 05:20:30 PM
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Hi, I'm using Methylamine in a reaction at a 4:1 molar ratio to the product being substituted.
What is the best way to recover the excess Methylamine freebase from the aqueous solution? I have tried boiling it out into HCl but it seems to generate too much heat and transfer too much water across. Has anyone tried blowing it through a trap into HCl or are there and common ways this is recovered?
Thanks in advance.
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I would add NaOH to get all Amin free in the solution and use vacuum and soft heat.
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1). In industry, methylamines are removed by extractive distillation.
https://www.researchgate.net/publication/245329246_Extractive_Distillation_A_Review
Extractive distillation can also be effectuated in the lab, but a special glassware and adequate experience are necessary.
2). Alternatively, you can remove MeNH2 by transferring into HCl solution, as you did, but you have to cool your trap because the solubility of gases (HCl and MeNH2) decreases by the heat that is generated during the exothermic neutralization.
3). A more risky way that might work is adding dimethylamine, which forms a ternary azeotrope with MeNH2 and water, at about 30-40oC and then azeotropy with ethanol at 78oC.
4). Methylamine has a relatively high latent heat of vaporization (200 cal/g = 837 J/gr) and therefore, evaporation is slow. Thus, you need enough time, in order to remove it under vacuum, after alkalinization.