Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Sona on May 29, 2017, 12:52:22 AM
-
If y2=4x and 0.1% error is incurred for x, the percentage error involved in y will be:
(a) 0.4 ,(b) 0.025, (C) 0.1, (d) 0.05
How to calculate this?
Can it be solved by just putting this value 0.1 in this equation and solving to get the value for y??
Please help
-
https://www.av8n.com/physics/uncertainty.htm#sec-crank3