Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: tiffae on August 05, 2017, 10:20:25 PM
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Hi all,
I'm a year 11 IB student in Australia and I'm currently doing an IA on enthalpy of combustion of alcohols. I've chosen to do 1-propanol, 2-propanol and 2-methyl-2-propanol.
I thought tertiary alcohols would have the highest enthalpy of combustion followed by secondary than primary.(because of the surface area) But apparently that's not the case? In the IB data booklet, 2-propanol's enthalpy of combustion is -2010 but -2020 for 1-propanol. Can anyone explain to me why is it the case???? I really appreciate it, thanks!!!
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What do you know about the difference in bonding between 1-propanol, and 2-propanol? Do you think that would affect the enthalpy of combustion?
XeLa
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Compare bond strength of C-OH on the basis of formation of free radical/carbocation after homolytic /heterolytic bond cleavage.More stable is the radical or Carbocation more easy to break bond or weak is bond.I think this will help you in comparing Heats of Combustions of primary, Secondary and tertiary alcohols.