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Chemistry Forums for Students => Organic Chemistry Forum => Organic Spectroscopy => Topic started by: aag on March 22, 2018, 12:01:22 AM

Title: How to analyse an IR and NMR to eliminate the Isomers
Post by: aag on March 22, 2018, 12:01:22 AM

So, I have an assignment that is about 4-chlorobenzaldehyde but I cannot find much information on it.

I have to deconstruct and analyse my IR but there is no information the collaborates with the 1300-1000 region. I was also wondering if someone could help with a quick analysis. The IR is different from most found on the internet and I was also wondering why that is (but the NMR is the same).

For the IR and the NMR we have to explain why the compound is 4-chlorobenzaldehyde and not its other isomers such as 2-chlorobenzaldehyde or 3-chlorobenzaldehyde.

Title: Re: How to analyse an IR and NMR to eliminate the Isomers
Post by: wildfyr on March 22, 2018, 09:46:26 AM

Here is a website I found (in ten seconds) on using FTIR to distinguish isomers (hint look between 900 and 700)
http://www.spectroscopyonline.com/distinguishing-structural-isomers-mono-and-disubstituted-benzene-rings-0?pageID=2

Why do you need to evaluate the 1000-1300 region?

If you have the NMR then distinguishing isomers should be dead easy.