Chemical Forums
Chemistry Forums for Students => Inorganic Chemistry Forum => Topic started by: Winga on June 24, 2006, 12:36:55 PM
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The principal axis of XeF4 is C4 axis, but I am not quite understand that it also coincides with a C2 axis.
Does it mean that the XeF4 is a rectangular base rather than square base?
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All C4 axes will have a coincidental C2 axis...only because a C4 axis implies that rotations of 90°, 180°, 270°, and 360° result in no change in the structure's orientation. To be a C2 axis, this only has to be satisfied by rotations of 180° and 360° - so a C4 is a special kind of C2.
Like you said, a rectangle has a C2, and a square has a C4 - but the square also has a C2 - after all, a square is just a special kind of rectangle. A C4 is a special kind of C2.
And P.S., a C4 also has a coincidental C1 :D.
And P.P.S., A C8, you may have guessed, has a coincidental C4, C2, and C1.
Does it mean that the XeF4 is a rectangular base rather than square base?
Not quite...and I hope it is clear after what I've said...if it's not, let us know...I've been off of my game for a while :(
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I see.
Thank you!
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C4 has 4 C2 perpendicular to it.
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C4 has 4 C2 perpendicular to it.
I'm sure you already know this, AWK, but just to clarify for other readers, this is only true for certain structures. The presence of a C4 axis does NOT imply four C2 axes perpendicular to it ... it just happens to be true for XeF4. It is entirely possible to have a C4 axis with NO perpendicular axes of symmetry.
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C4 has 4 C2 perpendicular to it.
I'm sure you already know this, AWK, but just to clarify for other readers, this is only true for certain structures. The presence of a C4 axis does NOT imply four C2 axes perpendicular to it ... it just happens to be true for XeF4. It is entirely possible to have a C4 axis with NO perpendicular axes of symmetry.
We just discuss abot flat squared structure. I did not say that this always is valid. And this statement concerns only an idealized structure.
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We just discuss abot flat squared structure. I did not say that this always is valid. And this statement concerns only an idealized structure.
Agreed. I said what I did just to clarify, in case someone decides to generalize a rule...we wouldn't want anyone to mislead themselves!