Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: Bor on June 11, 2018, 06:25:50 PM
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Hello, the question and all of the data is as follows:
There is an electrochemical cell with the reaction Cd(s) + Fe2+(aq) :rarrow: Cd2+(aq) + Fe(s) .
E0Cd2+|Cd = -403V and E0Fe2+|Fe = -0.447V .
Calculate the potential of such a cell.
also, I think there should have been a two-sided arrow in the reaction, not a one-sided.
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What answer did you calculate?
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We calculated the answer to be 0,0029V
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also, I think there should have been a two-sided arrow in the reaction, not a one-sided.
Potential difference is not large, but the direction of the reaction is quite obvious.
No idea how you got 0.0029 V, it is an order of magnitude too low.
It is a trivial question, my bet is you have overcomplicated it.
(BTW: -0.403 V, not -403 V)