Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Namossa on August 29, 2018, 02:26:42 PM
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Hi I have a question concerning this?
An acidified Fe2+ solution was titrated with permanganate solution. When titrated went 20 cm^3 0.02020 mol/dm^3 MnO4 solution. Determine the amount Iron expressed in gram in the first solution?
Here are my calculations
5Fe2+ (aq) + MnO4- (aq) + 8H+ --> 5Fe3+ (aq)+ Mn2+ + 4H2O
Fe Molar mass 55,935 g/mol
n=c * (V/1000)
0.02020 * (20/1000) 4*10^-4
Ratio MnO4: Fe2+
1:5
4* 10^-4 * 5 =2,02 *10^-3
2,02 *10^-3* 55,935= 0.1129887 g
The correct answer is 0.01127g
What I am doing wrong
please help
Thank you!
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Determine the amount Iron expressed in gram in the first solution?
What does it mean. Your calculation for the 20 cm³ is correct, but was this sample taken from something ?
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It was not written in the question.
Any more comments?
Thanks!
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Then it can be only 2 cm³ solution or it was 0,00202 mol/l concentration.
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I solved it thx!
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What was the reason now?