Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: lissydoll206 on July 13, 2006, 10:06:55 AM
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When you react propanol with the CrO3 and H2SO4, what is the product of the reaction? Does the OH substituent group just become an O double bonded on the end of the propane? I am confused. Any help would be greatly appreciated.
(CH3)2CH-OH ---- CrO3, (HO)2SO2 ---------> product???
Thanks!
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Look up oxidation of alcohols in any organic chemistry textbook.
or http://www.google.co.uk/search?hl=en&safe=off&rls=GGLR%2CGGLR%3A2005-38%2CGGLR%3Aen&q=alcohol+oxidation+chromate&btnG=Search&meta=
The first result has the answer
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also look for Jones Reagent.. ;D
Oh, talking about oxidation..I also wanna ask this..it's about oxidation mechanism..
In my chemistry textbook for school student..it's written that oxidation process in alcohol is taking a hydrate form as a transition then, one of the -OH group will release H+ and become a carbonyl bond...is it true? I just confused with that..
maybe it's like this:
R-CH2-OH --oxidator--> [R-CH(OH)2] ---> R-CH=O --> RCO2H
Simply ask, can anyone tell me how the mechanism is?? ;D
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The hydrated aldehyde is oxidised to the carboxylic acid.
RCHO ----Water----> RCH(OH)2 ---Ox----> RCH(OH)O-CrO3H ------> RCO2H + H2CrO3
The highlighted H is the one that is removed by CrO3.
As far as I know, that is the mechanism.
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Okay..I get it now..thanks for da reply.. ;D