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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: xstrae on July 13, 2006, 11:04:29 AM

Title: High School Atomic Physics
Post by: xstrae on July 13, 2006, 11:04:29 AM

This problem i came across stumps me. can someone please guide me?

A series of lines in the spectrum of atomic hydrogen lies at wavelengths 656.46 , 482.7, 434.17, 410.29 nm. What is the wavelength of the next line in the series??
where do i begin?? ???

thanks in advance

Title: Re: Atomic structure - hydrogen spectrum
Post by: Albert on July 13, 2006, 11:25:32 AM

Check these out:

http://hyperphysics.phy-astr.gsu.edu/hbase/hyde.html

http://teacher.pas.rochester.edu/phy_labs/Hydrogen/Hydrogen_spectrum.html

The former, in particular, could be rather useful, in my opinion.

Title: One more q related to atomic structure based on de broglie wavelength
Post by: xstrae on July 13, 2006, 11:32:23 AM

Calculate the de broglie wavelength of an electron that has been acceleraed from rest through a potential differnece of 1kV.

 ???

Title: Re: Atomic structure - hydrogen spectrum
Post by: xstrae on July 13, 2006, 12:26:56 PM

yup thanks a lot. the first was helpful.
all the wavelengths given above correspnd to the visible region of the electromagnetic spectrum. Therefore they belong to the Balmer series. so substituting in the formula, we get 396nm as the next in line. thanks! :)

Title: Re: High School Atomic Physics
Post by: Donaldson Tan on July 13, 2006, 02:16:45 PM

Quote from: konichiwa2x on July 13, 2006, 11:32:23 AM

Calculate the de broglie wavelength of an electron that has been acceleraed from rest through a potential differnece of 1kV.

The kinetic energy of the electron is there 1000 electron-volt (E = Q*V)

Since the electron mass is known, what is the momentum that corresponds to 1000 electron-volt kinetic energy?

you should be able to calculate the wavelength from the momentum using debroglie's equation.

Title: Re: High School Atomic Physics
Post by: xstrae on July 14, 2006, 01:41:03 PM

thanks a lot!  :)