Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: AmberLynn on September 01, 2004, 10:18:31 PM
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An irregularly shaped piece of lead weighs 10.0g It is carefully lowered into a graduated cylinder containing 30mL of ethanol, and it sinks to the bottom of the cylinder. To what volume does the ethanol rise? :-\ i need it by 12 am tonight
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This is a simple volume-density question. The ethanol will rise by the volume of the lead. This can be simply calculated using the equation volume = mass/density. My SI data book gives the density of lead at 11.4g/cm3
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yea, but i still dont get it.... it gives me a choice of 4 answers it could be, and i'm not getting any one of them. The 4 answers are a)31.9 b)30.9 c) 31.2 d0 30.2
d=m/v so... d=10.0/30.0 and that gives me .33 repeating which isnt right. I'm so lost please help :'(
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It has nothing to do with the volume of the ethanol, the same question could be asked with water or chloroform etc. All that is required is the volume of the piece of lead. This is equal to mass/density = 10.0/11.4 = 0.88cm3 = 0.88mL. So the volume of the ethanol will be increased by 0.88, Therefore the answer is 30 + 0.88 = 30.88mL
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It has nothing to do with the volume of the ethanol, the same question could be asked with water or chloroform etc. All that is required is the volume of the piece of lead. This is equal to mass/density = 10.0/11.4 = 0.88cm3 = 0.88mL. So the volume of the ethanol will be increased by 0.88, Therefore the answer is 30 + 0.88 = 30.88mL
Yeah just the Archemedis Principle.