Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: sanguine on January 02, 2019, 01:15:59 AM
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The Zn in a 0.7162g sample of powder was titrated with 21.27mL of 0.01645M EDTA. Calculate the %Zn in this sample.
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1/1 Ratio
0.01645 M x 0.02127 L = 0.000349891 mol
Mass of Zn: 0.000349891 mol x 65.39 g = 0.02287 g
% in sample: 0.02287 g / 0.7162 g (sample weight) = 3.195%
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Looks OK.