Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: AussieKenDoll on March 06, 2019, 10:27:49 PM
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How do I calculate the volume required to prepare 250.0 ml of 1 mol dm-3 CH3COOH. Molar mass of acetic acid = 60.05 g mol-1 Density = 1.05 g cm-3
Assay = 99.7%
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If the concentration is 1 mol/l how much mole you need for 250 ml?
Which mass correspond to it?
Which is the result calculate to 100%?
Which volume you get?