Chemical Forums
Chemistry Forums for Students => Undergraduate General Chemistry Forum => Topic started by: zeroh6x on August 06, 2006, 10:32:59 AM
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Calculate the amounts of acid and base forms of the buffer needed to prepare 2 L of a 0.1 M acetate buffer, pH 5.2.
Here is what i did so far but couldn't finish it. anyone can help me please?
PH = pKa + log [salt ]/ acid
pH - pKa = log salt /acid
5.2 - 4.74 =log salt/acid
0.46 = log salt - log (2 x 0.1 )
= log salt - (-0.6989)
0.46 - 0.6989 = log salt
0.2389 = log salt
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5.2 - 4.74 =log salt/acid
From here I would go for
salt/acid = 100.46
and
salt + acid = 0.1