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41
Generic Discussion / Re: Get rid of the smell of ethanol
« Last post by Hunter2 on April 12, 2024, 08:20:27 AM »
Ethanol like vodka, has it own odor.  This cannot be changed.
Industrial ethanol is mixed with other chemicals Pyridin, MEK, and others. to avoid to drink it.
42
Generic Discussion / Get rid of the smell of ethanol
« Last post by Zana on April 12, 2024, 05:39:35 AM »
Is there a way to get rid of the smell of ethanol? To finally get odorless ethanol?
43
Sorry for maybe too late reply, I hope you were able to solve the column.
Anyway, here is my advice:

1) your column feels way too small for such amount. I prefer to use shorter but wider columns because its faster (you trade number of theoretical plates for their size and since the size has square relation to column diameter unlike the number of plates vs lenght which is linear). I would use 2 or 3 cm diameter and maybe 10-12 cm of silica in the column

2) for such amount, taking 2 ml fractions is overkill. 10 or 20 is good volume here in my opinion - cuts time, glassware use and number of TLCs to do.

3) you dont have to TLC all your fractions, I like to make a grid on TLC plate, check which fractions has SOMETHING and then elute only those containing something. I also run TLC during the column. This way you can figure out when to stop (you obviously stop when your compound of interest is eluted)

4) as one of my advisers told me commonly: "Color is five percent". It is SOME indication but hardly conclusive. Ofc, after you run the same column multiple times you can get more information from the color of fractions ("my compound is eluting AFTER this yellowish band so I can take all the stuff into a beaker before it starts eluting")

5) you can increase polarity of your mobile phase over time to get better separation

6) Based on by experinece, I feel you might need to run more fractions, run TLC on maybe each fifth fractions to get SOME idea but 90 ml of mobile phase doesnt seem to be enough in your case.
44
Volume * density of the dry air, gets me the dry air that was put in at the beginning of the experiment, as 0.317g.

Using 0.317g and subtracting from 131.4413 gets me the mass of an empty (vacuum) flask with the stopper and plug

Not exactly - you are ignoring the buoyancy. Internal air cancels out (mass of the air inside is identical with the buoyancy). No need to subtract 0.317 g here.

0.317 g is the buoyancy error of the weighing of a CONTENT of the flask. It will produce a small relative error in the flask volume, but a large relative error in the CO2 mass.

You have ignored an error in the flask mass, error that depends on the volume of the glass itself (not the flask volume, but volume of the material from which the flask is made). But in the end it doesn't matter either, as it the same in all cases, so it cancels out when you subtract them to find out masses of the gas/liquid that fills the flask.
45
Undergraduate General Chemistry Forum / Re: Reverse Diffusion Demonstration
« Last post by S_Ch_S on April 11, 2024, 03:15:45 AM »
Another interesting link:
https://www.sciencedirect.com/science/article/abs/pii/S0378437120309973

Quote from the intro:
"It is shown that there is a deep analogy between the parameters of thermodynamic and economic systems (markets)"

Your view of the world that you described above shifts the perspective of looking at things completely. And it seems to be touching a much deeper level...than what is usually observed..  It is very interesting to think for example volatility in markets as a non-equilibrium state...it literally is. Thanks again!
46
Chemical Engineering Forum / flexy bag discharge
« Last post by RomanKatz on April 11, 2024, 02:46:40 AM »
Hello, Friends

We Order low viscosity Base oil and concentrate coolant in flexy bags in containers that are brought by a trailer and remain on a wagon till the discharge.
(about 1.5m height). I connect a 2'' gear pump and flexible hose and transfer to IBC or a storage tank near by, it's valve about 2 m height. The thing is that i can't get the bag drained 100%. Even if folded or lifted. I think that too much is left, about 50 kg.
if it was 2-5 kg, fine but this is different.

Any advice?
47
You're right. sorry. I meant 43.44 gmol is the molar mass of the CO2.

I was tired.

Okay, so

Nevermind, I'll just take a picture and upload it.

https://imgur.com/a/TPLbKOg

And yes, I argued with the prof about the discrepancy, but he said "its just a matter of the mass of water being so large that the error by the air is going to be 0.01g" or something.

Cant remember it well.

Anyway, it made no sense at all to me. But yes, we were supposed to

[This is mass(Flask,stopper  + water) - (Flask,stopper + air) = mass of water - ~~mass of air~~??]

Correct, Using 396.64 minus 131.4413 gets me mass of the water. Mass of the water / density gets me the .26573L.

Volume * density of the dry air, gets me the dry air that was put in at the beginning of the experiment, as 0.317g.

Using 0.317g and subtracting from 131.4413 gets me the mass of an empty (vacuum) flask with the stopper and plug, which therefore is subtracted from the CO2 flask of 131.6014 to get me mass of CO2 at 0.47712g.

At this point an equation m/V = PM / RT is used. I can plug in m, V, P, R, and so the remaining equation is 1.795507 = 0.041327 * M.

Then divide both sides by 0.041327, and get M = 43.44 g/mol, where M is the molar mass.

48
Analytical Chemistry Forum / Re: TLC stain
« Last post by Babcock_Hall on April 10, 2024, 06:08:38 PM »
A test thioether stained nicely with basic permanganate.
49
Analytical Chemistry Forum / Re: TLC stain
« Last post by Babcock_Hall on April 10, 2024, 01:15:47 PM »
Acta Chemica Scandinavica 1960 14:1980-1984.  Stig Akerfeldt used 1% CuCl2 in 50% ethanol containing 5% ammonia as a spray reagent to produce black spots for cysteamine S-phosphate on paper.  It also reacts with thiophosphate, but I am not sure how other compounds would behave.

Erratum
In regards to my previous message, I had a look at the 1969 paper by Howard and Baldry.  They did not use chloramine T for TLC detection; it was a reagent.
50
Undergraduate General Chemistry Forum / Re: Mole Fraction and average molar mass
« Last post by Hunter2 on April 10, 2024, 12:42:41 PM »
Well but it doesn't says how many moles or g of SO2 and SO3 is in the mixture.

n(tot) = n1 + n2
Using  n = m/M
n(tot) = m1/M1 + m2/M2

And m(tot) = m1 + m2

Solve for m1 and m2
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