[Dergyll]

Hey guys, just did a cool lab today on precipitation reaction (double replacement)

I have a question based on a question my teacher gave us. The chemical equation for the reaction is this: Pb(NO₃)₂(aq)+2KI(aq)  ---> PbI₂(s)+2K(NO₃)(aq)

I know how the nitrate and iodide switch places for the double replacement and the remaining "speckled" crystal things in the test tube are precipitates (lead iodide to be more specific). How can this connect to the activity series? I know that the activity series tells us how reactive (easy to oxidate) the element is, and I see that lead is farther down the activity series than Potassium, how could this reaction be explained with lead and potassium's position on the activity series?

Any help is appreciated
Derg

[UnintentionalChaos]

This is unrelated to the reactivity series. A single replacement (which is a redox reaction) would be related to the reactivity series. The experiment you did was all about solubilty (or lack therof).

There isn't necessarily a "switching of places" just insolubility of one of the pairs of ions that you mixed. In aqueous solution, most salts behave, more or less like ion soup.