[physicsstudent]

I'm working on a science fair project, and I'm working with titrations. I need to dilute the HCl I'm going to be working with to a pH of 3 or 4.

The HCl that I have is 12M and I was wanting to make 1L of solution with a pH of 4.

I know that I should be using the M1V1=M2V2 formula, but I'm not sure if I have the individual numbers right.

I used H+=antilog[-pH] to get that the concentration of the final solution should be 1.0x10^-4M, but what do I do after that?

[Borek]

So far you are OK (that' assuming you use pH 4 HCl solution for titrations, I would go for pH 1). You know M1 (10^-4), V1 (1L), M2 (12) - you need V2. It can't be simpler then that

[Kryolith]

You calculated the concentration, so now you need to know how much moles of HCl are needed for 1 l of your solution.



Now what volume of a 12M solution is needed for 10^-4 mol? This volume is filled up to 1 l and you're done.

Always remember c=n/V