June 05, 2024, 10:51:04 AM
Forum Rules: Read This Before Posting


Topic: Molar entropy annoying question  (Read 5875 times)

0 Members and 1 Guest are viewing this topic.

Offline scrum

  • Regular Member
  • ***
  • Posts: 14
  • Mole Snacks: +0/-0
Molar entropy annoying question
« on: January 30, 2008, 08:56:44 PM »
The molar entropy of helium gas at 25°C and 1.00 atm is 126.1 J K-1 mol-1. Assuming ideal behavior, calculate the entropy of the following.
Quote
(a) 0.215 mol He(g) at 25°C and a volume of 5.74 L
 J/K
(b) 4.24 mol He(g) at 25°C and a volume of 3442.4 L
 J/K

I looked at this and i figured since 126.1 is J/Mol K and they want J/K all i do is multiply by mols and not use the other stuff for it.

I did part (a) this way, doing .215 * 126.1 = 27.1

and then for part (b) i did the exact same thing 4.24 * 126.1 and got 534.664 which is incorrect. i also tried variations like 534, 534.7 , 534.66, but they are all wrong.



Offline Yggdrasil

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 3215
  • Mole Snacks: +485/-21
  • Gender: Male
  • Physical Biochemist
Re: Molar entropy annoying question
« Reply #1 on: January 31, 2008, 11:40:59 PM »
IIRC, the entropy of the gas will depend on its volume (and hence pressure).  So, in your calculations you should include the ΔS for the isothermal expansion/compression, needed to get the correct volume/pressure.

Sponsored Links