Okay, for your reaction here, let's break it down, firstly, HI, what is it? Well, under normal conditions it is a gas, how does one react a gas with water? The answer would be to bubble it through the water. But then what happens? Because the molecule is a small polar one, it will dissolve in water fairly easily
HI (g) + H
2O (l)
HI (aq)
Then, the next reaction is what you are talking about, the dissociation or 'breaking up' of the HI (aq). As you probably know, there are acids and bases, in the simplest case, an acid is a proton (H
+) donor and a base is a proton acceptor. HI (aq) is a strong acid, meaning that it donates a proton readily, because the H-I bond is relatively weak (along with some other factors not to be worried about for the moment). Also, the bond formed between H
2O and H
+ is a stronger bond than an H-I bond, meaning that it releases more energy. SOME reactions occur in order to achieve minimum energy, in this case, this is one of them, because breaking the H-I bond requires less energy than is released when the O-H bond forms so overall, the system loses energy.
HI (aq) + H
2O (l)
H
3O
+ (aq) + I
- (aq)