October 31, 2024, 08:14:48 PM
Forum Rules: Read This Before Posting


Topic: How can the electronic structure of 1Σ+g singlet oxygen be obtained by G09  (Read 2875 times)

0 Members and 1 Guest are viewing this topic.

Offline mahyar310

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
I used several methods to get the electron structure of 1Σ+g singlet oxygen (second excited state) in Gaussian09 or Jaguar9.8 (Schrodinger suites), for example

Quote
# opt ucis=(singlets,root=2)/6-31+g(d,p)
singlet sigma+g oxygen
0 1
O 0.00000000 0.00000000 0.70417356
O 0.00000000 0.00000000 -0.70417356
But the results are 1Δg singlet oxygen (first excited state)?
https://en.wikipedia.org/wiki/Singlet_oxygen

or

Quote
# opt casscf(6,6,nroot=X)/6-31+g(d,p)
Title
0 1
O 0.00000000 0.00000000 0.60287642
O 0.00000000 0.00000000 -0.60287642

when X=1 or casscf(6,6)
Final one electron symbolic density matrix:
1 0.194995D+01 =π1 with two electron
2 0.194995D+01=π2 with two electron
3 0.104995D+01 = π*1 with one electron
4 0.104995D+01= π*2 with one electron
5 0.902987D-04 = σ *empty
6 0.119828D-03 = Empty
when X=2
Final one electron symbolic density matrix:
1 0.192295D+01
2 0.192295D+01
3 0.107694D+01
4 0.107694D+01
5 0.873522D-04
6 0.121063D-03
when X=3
Final one electron symbolic density matrix:
1 0.189273D+01
2 0.189273D+01
3 0.110413D+01
4 0.110413D+01
5 0.128968D-03
6 0.615265D-02

All three states are the same???! all are 1Σ+g :o

http://www.molpro.net/pipermail/molpro-user/2009-September/003319.html

Sponsored Links