Hi All,
I have monomer Methly-Acrylate coming with an MeHQ inhibitor inside.
I would like the polymerise the monomer with a comonomer, so i have to remove inhibitor prior polymerisation.
One method (I read from an article) is to wash monomer with aqueous NaOH caustic solution. So, the MeHQ reacts with NaOH, turns into salt.
Then, we will have a mix of two liquids, Methyl-acrylate monomer and water (containing NaOH and salt of NaOH/MeHQ).
After, these two liquids can be separated by using funnel.
But, i read that there will be small amount of water dissolved in Methyl-Acrylate phase.
So that means, after i collect Methly-acrylate at bottom of the funnel, there will be small amount of water and dissolved NaOH in monomer.
And, i do not want this residual NaOH because it can affect the quality of polymerisation process.
- How can i minimise the residual Water/NaOH solution in Methyl-Acrylate ?
- If i do : Let's say first i wash Methyl-acrylate with 0.1N aqueous NaOH , and second wash with 0.05N , and third wash with 0.01 N. That would be a good solution to remove all MeHQ and minimise the NaOH in Methyl-Acrylate ?
Please, let me know if there are any other precise way to do this.
Regards.