[yourdeath01]

**Being asked to Calculate the mass and volume of 150 mmol of benzaldehyde, and the theoretical yields of benzoin, benzyl, and benzilic acid expected from that much benzaldehyde.**

Here are the reactions for everything:

part a: https://imgur.com/dQSUru1

part b: https://imgur.com/8Ae7aSu

part c: https://imgur.com/Xa0Zf8J

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**For part a heres my answer for mass and volume of 150 mmol of benzaldehyde + theoretical yield of benzoin** : https://imgur.com/nrV1P2I

Remember from the equation we see 2 molecules of benzaldehyde = 1 molecule of benzoin so 150 mmol/2 = 75 mmol of benzoin produced right so 0.075 mols x mw of benzoin to get theoretical yield correct?

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**For part b theoretical yield of benzyl is going to be 150 mmol of benzyaldehyde = 150 mmol of benzyl correct? Not 75 mmols of benzyl? So 0.15 mols x mw of benzyl = theoretical yield of benzyl correct?**

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**For part c for theoretical yield of benzilic acid: https://imgur.com/LpavJm0**

Isn't this going to be 150 mmol benzaldehyde = 75 mmols of benzilic acid or what you think? 0.075 mols x mw of benzilic acid = theoretical yield correct?

I am just not sure why for part b we use 150 mmol benzaldehyde = 150 mmol benzyl

but in part c its 150 mmol = 75 mmol benzilic acid?

For part a I understand 150 mmol benzaldehyde = 75 mmol benzoic cos the reaction shows 2:1 ratio but for part b and c it looks like 1:1 ratio to me so i don't know...

[AWK]

If you look at molecular formulas
2C₇H₆O => C₁₄H₁₂O₂
0.15 mol ... 0.075 mol (mass unchanged)
C₁₄H₁₂O₂ => C₁₄H₁₀O₂ + H₂
0.075 mol ... 0.075 mol + 0.075 mol H₂ (mass of aldehyde - mass of 0.0075 H₂)   
C₁₄H₁₀O₂ + H₂O => C₁₄H₁₂O₃
0.075 mol + 0.075 mol of H₂O ... 0.075 mol (mass of aldehyde + mass of 0.075 mol of oxygen atoms)