the solubility product of SrCO3 is 1.6*10*-9. To a solution containing .175g of Sr was added solid Na2CO3 unitil the CO3 concentration was 2.50*10-6. What mass of SrCO3 was precipitated?
SrCO3 = Sr + Na2CO3
1.6*10*-9/ 2.5*10*-6=Sr
Sr=0.00064 mol/L* Molar mass to find the mass
i don't know know whether this is the right method please help.