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In a particular reaction between copper metal and silver nitrate, 12.7g Cu produces 38.1g Ag. What is the percent yield of silver in this reaction? Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
My answer: 12.7 g Cu = 0.19998 mol Cu = 0.3997 mol Ag = 43.116 g Ag (theoretical yield), 38.1/43.116 x 100% = 88.37%