June 17, 2024, 08:45:39 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: E = mc2  (Read 1640 times)

0 Members and 1 Guest are viewing this topic.

Offline NathanielZhu

  • Regular Member
  • ***
  • Posts: 24
  • Mole Snacks: +2/-2
E = mc2
« on: May 04, 2012, 08:30:13 PM »
How kJ are released to form one mole of 204Pb from protons and neutrons if the atom has a mass of 203.973020 amu?
------------------------------------------------------------------------------------

I think I'm supposed to use E = mc2
I just plug in E = (.203973020kg)(3 X 10^8)^2.
I get a wrong answer.
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27701
  • Mole Snacks: +1804/-411
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: E = mc2
« Reply #1 on: May 05, 2012, 02:36:08 AM »
What is a mass deficit for 204Pb?
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info
Pages: [1]   Go Up
« previous next »
Sponsored Links