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Topic: Equilibrum fraction  (Read 2125 times)

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Offline Big-Daddy

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Equilibrum fraction
« on: December 31, 2013, 02:59:13 PM »
Consider a reaction A+B  ::equil:: C+D. (K is known) We observe that fraction f of reactant B is reacted into products. How many possible mole ratios n0(B)/n0(A) can the reactants be reacted in to give this fraction f? Find all possible mole ratios.

My initial thinking was that B, of which fraction f was reacted, could be either the limiting reagent or the non-limiting reagent, so there should be two possible mole ratios. But once I approached the calculation I found only one solution (start from neq(B)=n0(B)*(1-f), neq(A) = n0(A) - f*n0(B), neq(C)=neq(D)=f*n0(B) and there is only one possible solution of n0(B)/n0(A) here). How many solutions are there - and why - and how do I get to all?

Offline mkurek

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Re: Equilibrum fraction
« Reply #1 on: December 31, 2013, 04:40:31 PM »
You said that K is known? K is meaning the equilibrium constant of this reaction right?

If so, that would be your place to start. Look up equilibrium constants, and then see what it means if K is less than, greater than, or equal to 1. That should get you pushed in the right direction.

Online Borek

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Re: Equilibrum fraction
« Reply #2 on: January 01, 2014, 07:44:24 AM »
Mixing limiting reagents and equilibrium constants makes no sense.
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Offline Big-Daddy

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Re: Equilibrum fraction
« Reply #3 on: January 02, 2014, 11:35:52 AM »
Mixing limiting reagents and equilibrium constants makes no sense.

You haven't understood my initial thinking, clearly because my initial thinking was wrong. But I won't bother you with this explanation since I think I've got it now. In short, only if information is given pertaining to the limiting reagent or to a non-limiting reagent specifically, and other information does not enable the limiting reagent to be specified for the case studied, you need to work in terms of "limiting reagent" and "non-limiting reagent" and then consider each possible identity for the limiting reagent only after calculations. But this wasn't needed for the OP question.

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