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Topic: Substitution and elimination reaction  (Read 2256 times)

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Offline tvtokyo

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Substitution and elimination reaction
« on: March 12, 2015, 12:05:57 AM »
I have this problem:
I known that reaction with TsOH would replace -OH groups with TsO (substitution reaction). (Et)3N would therefore act as a base to abstract H to form an alkene. The problem is i know it should be an E1cb reaction but how do I obtain an alkene? I tried to draw the mechanism but comes to no solution can anyone help or am i in the wrong direction? Thank you!


Offline OrgXemProf

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Re: Substitution and elimination reaction
« Reply #1 on: March 12, 2015, 09:00:34 PM »
If you're convinced that the product MUST be a substituted cyclopent-2-en-1-one and that the reaction MUST proceed via an E1cb mechanism, then you might consider the following reaction sequence:

1. Use Et3N + H3C-SO2Cl to convert ROH into the corresponding mesylate ester, ROMs. Now you have a good leaving group.

2. Use Et3N to abstract the O=C-CHOMs proton to form a resonance-stabilized carbanion.

3. In a subsequent step eliminate -OMs to form a carbene, which then is likely to undero 1,2-hydride shift to afford the desired substituted cyclopent-2-en-1-one.

Just wondering: Are you working backwards from the answer, or do you simply consider formation of an alpha,beta-unsaturated ketone to be the most likely outcome given the reaction conditions that you posted?


Offline tvtokyo

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Re: Substitution and elimination reaction
« Reply #2 on: March 13, 2015, 01:13:55 AM »
Just a simple assumption (i.e. not work back form answer)
Thanks for your reply :D

I have another question
For this reaction would it proceed via Sn2 or elimination
I think SN2 since the solvent is polar aprotic and SH- is not really a strong base???
So I think SH would substituted Br with a inversion in configuration?? Thanks!

« Last Edit: March 13, 2015, 03:07:39 AM by tvtokyo »

Offline orgopete

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Re: Substitution and elimination reaction
« Reply #3 on: March 13, 2015, 05:00:26 PM »
I have my doubts that the enone is the product.
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