[Runner19]

I'm placing approximately 30 mL of 1 M NaOH in a 600-mL beaker and adding 270 mL of distilled water. I need to calculate the approximate concentration of the NaOH solution.

My first thought is to use the equation M = n/V
where M is molarity, n is moles, and V is volume.

The total volume would 300 mL, or 0.3 L.

I'm stuck on how to find the moles of NaOH. Can anyone point me in the right direction?

[Borek]

I'm stuck on how to find the moles of NaOH. Can anyone point me in the right direction?

Hint: you have already listed the necessary equation.

[RiverviewTutor]

(1mol NaOH)/(1L solution) * (0.3 L solution) = 0.3 mol NaOH.  No matter how much water you add into the solution afterwards, the total moles of NaOH will not change.  Therefore the answer is 0.3 mol NaOH. 

[billnotgatez]

@RiverviewTutor
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