September 23, 2019, 08:10:07 AM
Forum Rules: Read This Before Posting

Topic: Got this question on electrolysis involving charge on ion with calculation  (Read 187 times)

0 Members and 1 Guest are viewing this topic.

Offline Usman

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0

During electrolysis 0.02 moles moles of metal X is deposited on cathode when 0.12 moles of e- are passed through molten chloride of X. What is the formula of the chloride?

I have tried solving it and my answer is XCl6 which is incorrect. The correct answer given is XCl3. In the explanation the book says that 0.06 moles of e- have flown to cathode and goes on to divide the no. of moles of e- at cathode by no. of moles metal X (0.06/0.02) so it's 3 which means 1 atom of X gains 3 e-'s, giving X +3 charge. What I do not get is what about the other 0.06 mole of e-'s. Isn't metal X supposed to gain all of the 0.12 mole of e-'s ? Shouldn't cathode have the total 0.12 mole of e-'s?

Your answers and explanations will help me a lot, thanks.

Online Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 25198
  • Mole Snacks: +1656/-397
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
XCl6 looks OK to me.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation,,

Sponsored Links