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Topic: Ideal Gas Equation  (Read 982 times)

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Offline Phoebe

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Ideal Gas Equation
« on: August 24, 2019, 06:25:12 AM »
Hello

I'm working on a question that asks me to use the ideal gas equation to calculate the corresponding volume (in litres) of oxygen gas at a standard atmospheric pressure (SATP) of 25degrees Celsius and 100 kPa (1bar)

 - the question relies on a previous calculations of O2n = 18.49

  T = 25 + 273
     = 298

So Pv=nRT and to solve for V the equation rearranges to V = nRT/P

 18.49 x 8.314 x 298 / 100

    = 45710.306


Just to double check I typed all my working out into an online ideal gas calculator and there I get an answer of 458.128 Litres

Have I forgotten to convert units somewhere?

appreciate any insight :)

Offline Vidya

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Re: Ideal Gas Equation
« Reply #1 on: August 24, 2019, 07:33:50 AM »
R value which you have selected is Pa.m3/mol.L
Convert kPa to pascal and then you will get answer in m3
Now convert m3 to L  and you will get right answer.

Offline Phoebe

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Re: Ideal Gas Equation
« Reply #2 on: August 24, 2019, 08:31:55 AM »

  Ah! Thank you!!! I had forgotten to convert from cm3 to L
 
  Bless the internet and you Vidya :)

  Thanks so much

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